How to get the full url in express.js?

1. The protocol is available as req.protocol. docs here

   1. Before express 3.0, the protocol you can assume to be http unless you see that req.get('X-Forwarded-Protocol') is set and has the value https, in which case you know that's your protocol

2. The host comes from req.get('host') as Gopal has indicated

3. Hopefully you don't need a non-standard port in your URLs, but if you did need to know it you'd have it in your application state because it's whatever you passed to app.listen at server startup time. However, in the case of local development on a non-standard port, Chrome seems to include the port in the host header so req.get('host') returns localhost:3000, for example. So at least for the cases of a production site on a standard port and browsing directly to your express app (without reverse proxy), the host header seems to do the right thing regarding the port in the URL.

4. The path comes from req.originalUrl (thanks @pgrassant). Note this DOES include the query string. docs here on req.url and req.originalUrl. Depending on what you intend to do with the URL, originalUrl may or may not be the correct value as compared to req.url.

Combine those all together to reconstruct the absolute URL.

  var fullUrl = req.protocol + '://' + req.get('host') + req.originalUrl;

I found it a bit of a PITA to get the requested url. I can't believe there's not an easier way in express. Should just be req.requested_url

But here's how I set it:

var port = req.app.settings.port || cfg.port;
res.locals.requested_url = req.protocol + '://' + req.host  + ( port == 80 || po
rt == 443 ? '' : ':'+port ) + req.path;

Instead of concatenating the things together on your own, you could instead use the node.js API for URLs and pass URL.format() the informations from express.

Here is a great way to add a function you can call on the req object to get the url

  app.use(function(req, res, next) {
    req.getUrl = function() {
      return req.protocol + "://" + req.get('host') + req.originalUrl;
    }
    return next();
  });

Now you have a function you can call on demand if you need it.

You need to construct it using req.headers.host + req.url. Of course if you are hosting in a different port and such you get the idea ;-)

my setting is here

params['host_url'] = req.protocol + '://' + req.headers.host + req.url;

I would suggest using originalUrl instead of URL:

var url = req.protocol + '://' + req.get('host') + req.originalUrl;

See the description of originalUrl here: http://expressjs.com/api.html#req.originalUrl

In our system, we do something like this, so originalUrl is important to us:

  foo = express();
  express().use('/foo', foo);
  foo.use(require('/foo/blah_controller'));

blah_controller looks like this:

  controller = express();
  module.exports = controller;
  controller.get('/bar/:barparam', function(req, res) { /* handler code */ });

So our URLs have the format:

www.example.com/foo/bar/:barparam

Hence, we need req.originalUrl in the bar controller get handler.

I use the node package 'url' (npm install url)

What it does is when you call

url.parse(req.url, true, true)

it will give you the possibility to retrieve all or parts of the url. More info here: https://github.com/defunctzombie/node-url

I used it in the following way to get whatever comes after the / in http://www.example.com/ to use as a variable and pull up a particular profile (kind of like facebook: http://www.facebook.com/username)

    var url = require('url');
    var urlParts = url.parse(req.url, true, true);
    var pathname = urlParts.pathname;
    var username = pathname.slice(1);

Though for this to work, you have to create your route this way in your server.js file:

self.routes['/:username'] = require('./routes/users');

And set your route file this way:

router.get('/:username', function(req, res) {
 //here comes the url parsing code
}

I actually discovered that by using this code below you can get your url. Then proceed to slicing it up and deciding what next.

app.use(function(req, res, next) {
console.log(req.originalUrl);
res.send(req.originalUrl);
  });

Using url.format:

var url = require('url');

This support all protocols and include port number. If you don't have a query string in your originalUrl you can use this cleaner solution:

var requrl = url.format({
    protocol: req.protocol,
    host: req.get('host'),
    pathname: req.originalUrl,
});

If you have a query string:

var urlobj = url.parse(req.originalUrl);
urlobj.protocol = req.protocol;
urlobj.host = req.get('host');
var requrl = url.format(urlobj);