is ENOENT from fs.createReadStream uncatchable?

Question

is ENOENT from fs.createReadStream uncatchable?

I'm not able to catch ENOENT of fs.createReadStream(). Is this an asynchronous function , which throws exception in a different closure-chain ?

$ node -v
v0.10.9
$ cat a.js
fs = require('fs')

try  {
  x = fs.createReadStream('foo');
} catch (e) {
  console.log("Caught" );
}

$ node a.js

events.js:72
        throw er; // Unhandled 'error' event
              ^
Error: ENOENT, open 'foo'

I am expecting 'Caught' to be printed rather than error stack !

node.js

Answer 1

fs.createReadStream is asynchronous with the event emitter style and does not throw exceptions (which only make sense for synchronous code). Instead it will emit an error event.

var fs = require('fs')

var stream = fs.createReadStream('foo');
stream.on('error', function (error) {console.log("Caught", error);});
stream.on('readable', function () {stream.read();});