How to get filepath of called prototype method

Question

How to get filepath of called prototype method

I have the following example:

// MyType.js

function MyType(){}
MyType.prototype.getFile = function(){
   return __filename;
}

// SubType.js

var util = require('util');
function SubType(){}
util.inherits(SubType, MyType);

// test.js

var assert = require('assert'),
    subtype = require('./SubType'),
    myObject = new subtype();

assert.equal(myObject.getFile(), '/some/path/SubType.js'); // currently it fails, obviously

I know __filename doesn't work that way, but I was hoping there's a alternate late binding version of __filename or something equivalent?

javascript
node.js

Answer 1

Does the following code return the correct fileName?

function MyType(){
  this.__fileName=__filename;
  //maybe some other code you want to re use in subtype(s)
}
MyType.prototype.getFile = function(){
   return this.fileName;
}

One thing I'm not sure of when you re use parent constructor if the fileName is still correct:

function SubType(){
  MyType.call(this);
}