JSON removing property that contains empty values

Question

JSON removing property that contains empty values

I have a JSON object: var myObj = {'test':'' , 'test2': '1'}

I want a method on moving over the JSON object and removing all properties that have the empty value ''.

The result: myObj = {'test2': '1'}

javascript
json
node.js

Answer 1

This could be a possible solution:

var jsonObj = '{"test1":"","test2":"2","test3":"","test4":"4"}';
var jsObj = JSON.parse(jsonObj);

function removeNull(element,index,array){
    if (this[element] == ""){
        delete this[element];
    }
}
(Object.getOwnPropertyNames(jsObj)).forEach(removeNull,jsObj);

Check this link jsfiddle to see a working example.

To check whether the properties have been deleted or not:

alert(Object.getOwnPropertyNames(jsObj));

Hope it's useful!

Answer 2

This function do what u want.

var r = function(object){
   var _return = {};
   for ( var index in object ){
      if(object[index] != ''){
         _return[index] = object[index];
      }
   }
   return _return ;
};

Answer 3

Try this jsfiddle !

Code:

var myObj = {'test':'' , 'test2': '1','test3': '2'}

var obj = myObj;
for (var key in obj) {
  if (obj.hasOwnProperty(key)) {
    var val = obj[key];
      delete obj[key];
    console.log(val);
  }
}

for (var key in obj) {

    var val = obj[key];
    alert(val);
    //console.log(val);
}

If you want more info about understanding delete check this blog.